How to replace all occurences of character within a section of string.

Thanks for all of your help. I will try to play with this
some more..

Thanks.
 
Stacey

-----Original Message-----
From: Discussion of writing applications and components
using Visual
Basic .NET [mailto:VBDOTNETDISCUSS.DEVELOP.COM] On
Behalf Of Pardee,
Roy
Sent: Saturday, March 11, 2006 10:53 PM
To: VBDOTNETDISCUSS.DEVELOP.COM
Subject: Re: [VBDOTNET] How to replace all occurences of
character
within a section of string.

Man, this is really close:
Imports str = System.Text.RegularExpressions

Private Function x(ByVal intext As String) As String
   Dim out As String
   Dim rgx As New
str.Regex("(?<before>.*)(?<src>src="
".*"")(?<after>.*)",
str.RegexOptions.Singleline)
   For Each m As str.Match In rgx.Matches(intext)
      out &= m.Groups("before").ToString _
          &
m.Groups("src").ToString.Replace("\"
;, "/") _
          & m.Groups("after").ToString
   Next
   Return out
End Function
For some reason I don't understand, it's not replacing the
backslashes
on that last src="" line.  I don't have any
more time to play w/this,
unfortunately.
 
In real life, that 'out' var should be a stringbuilder I
guess...

________________________________

From: Discussion of writing applications and components
using Visual
Basic .NET on behalf of Rod Stephens
Sent: Sat 3/11/2006 7:18 AM
To: VBDOTNETDISCUSS.DEVELOP.COM
Subject: Re: [VBDOTNET] How to replace all occurences of
character
within a section of string.



> I did figure out a not so pretty way of
> doing it. Oh well. I guess it does work...
>
>     Private Function FixSlashInPath(ByVal thisfile As
String) As
String
>         Dim iLoop As Integer
>         Dim tempString As String
>         Dim newString As String
>         For iLoop =3D 0 To thisfile.Length - 5
>             If thisfile.Substring(iLoop, 3) =3D
"src" Then
>                 tempString =3D thisfile.Substring(iLoop
+ 5,
> thisfile.IndexOf(Chr(34), iLoop + 6) - (iLoop + 5))
>                 newString =3D
tempString.Replace("\", "/")
>                 thisfile =3D
thisfile.Replace(tempString, newString)
>             End If
>         Next
>         Return thisfile
>     End Function

Here's a more regular-expression-ey attempt. It searches
for the pattern
"[^"]*" (note that the leading and
trailing quotes are part of the
pattern),
which matches a quote, followed by any number of non-quotes,
followed by
a
quote. The code loops through the matches making the
replacements. I
replaced / with ? in the example to better see what it was
doing.

Private Sub btnReplace_Click(ByVal sender As System.Object,
ByVal e As
System.EventArgs) Handles btnReplace.Click
    Dim input As String = txtInput.Text
    Dim result As String = ""
    Dim next_unmatched As Integer = 0

    For Each match As Match In Regex.Matches(input,
txtPattern.Text)
        ' Add the text before the next match.
        If match.Index > next_unmatched Then
            result &= input.Substring(next_unmatched,
match.Index -
next_unmatched)
        End If

        ' Add the matched text.
        result &= match.Value.Replace("/",
"?")
        ' Debug.WriteLine("[" & match.Value
& "]")

        ' Set next_unmatched to the index
        ' of the last character in this match.
        next_unmatched = match.Index + match.Length
    Next match

    ' Add the rest of the string.
    If input.Length > next_unmatched Then
        result &= input.Substring(next_unmatched)
    End If

    ' Display the result.
    txtResult.Text = result
End Sub

You can download an example at:

    http://www.vb-helper.com/howto_net_replace_regex
_substrings.html

Unfortunately it's not much better than your code, although
it looks for
matched quotes rather than relying on the "src"
in the data. I couldn't
think of a way to make it substitute within the matches
automatically.
I'd
be interested to see it.

Rod

Rod Stephens, Author of "Visual Basic 2005
Programmer's Reference"
http://www.v
b-helper.com/vb_prog_ref.htm
Join the VB Helper mailing list at
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