repetition quantifier and named group

I have a little question: is it possible to use a repatition
quantifier
like "" but instead of "n" using a
reference to a named group? Ex.
{k<name>}

For example i need to detect a pattern like this:
"3;string;string;string;" or
"2;string;string;"

I had tryed using this patern "(d+);([^;]+;)"
or a named
equivalent version
"(?<howmany>d+);([^;]+;){k<howmany>}"
; but without
success. I think than "" can accept only a
number as "n".

Is there a workaround for doing this?

I hope you can help me, thanks a lot
Diego


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Archimede wrote:
> I have a little question: is it possible to use a
repatition quantifier
> like "" but instead of "n" using
a reference to a named group? Ex.
> {k<name>}
>
> For example i need to detect a pattern like this:
> "3;string;string;string;" or
"2;string;string;"
>
> I had tryed using this patern
"(d+);([^;]+;)" or a named
> equivalent version
"(?<howmany>d+);([^;]+;){k<howmany>}"
; but without
> success. I think than "" can accept only a
number as "n".
>
> Is there a workaround for doing this?

In Perl, this can be done by using an embedded code
construct
(??), like:

    (d+)(??{ "(;[^;]+){$1}" })

Or we can use some more regexes to do it, like using 'c',
'g' modifiers
and the 'G' anchor, i.e.:

while ( $str =~ /(d+)/g ) {
    my $num = $1;
    $str =~ /G((?:;[^;]*){$num})/gc and print
"$num$1";
}

Dont know how other tools handle this though.

Xicheng


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