Regex to search for and replace file names

I'm attempting to use regex in bulk file renaming software.
I have
files with names like "000901-030" and I'm
trying to get rid of the
extra zeros, but save the needed ones. The result I'm
trying to get in
this example is "901-30"

I thought perhaps something like ([^0*])([1-9])(\-) might
find the
zeros before the first number,  with a replace of \1.  I'm
obviously
missing something. Any advise on a more effective regex
would be
greatly appreciated. Also, if anyone had a link
recomendation to the
best regex info site that would also help.

Thanks in advance for any info.

Cheers,

dputz


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[^0*] is a char class (meaning of []) which searches for any
char that
is NOT (meaning of ^ in []) either zero or asterisk.

A solution without lookahead would be

^0*([^0].*)

an replace with \1
Aside: This will not match if the filename consists entirely
of zeros!


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Hi,

Sergei's solutions can usually be used straightaway without
any
problems, but in this case, I have the honour of making a
correction



What dputz needs is :


1. Find all zeros at the start of string, followed by any
digit.
(Positive lookbehind)
2. Find all zeros followed by a hyphen, followed by any
digit.
(Positive lookbehind, then Positive Lookahead)


He needs to replace 000901-030 with 901-30, NOT 901-03.


So, the Regex can be amended to :
^(0+)(?<=\d)|(?<=-)0(?=\d)


Regards, 


Cerebrus.


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yes, guys, i miserably misunderstood the spec! . Thanks
for posting
right solutions.

Sergei


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Sergei Z wrote:
> yes, guys, i miserably misunderstood the spec! . Thanks
for posting
> right solutions.
> 
> Sergei


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