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Thread: PHP Array regexp.
PHP Array regexp.
country flaguser name
United States		 2007-07-31 09:24:00 
Hello,

i need regexpresion that will match from this string:
$ARRAY_NAME['exp_one']['exp_two'] = 'text';

matches:
 1 - exp_one
 2 - exp_two
 3 - text

but sometimes in string can be 3 dimension array and regexp
should NOT
match this:

$ARRAY_NAME['exp_one']['exp_two']['exp_three'] = 'text';

And another thing with quotes, it could be ' or " :

$ARRAY_NAME['exp_one']['exp_two'] = "text";
$ARRAY_NAME["exp_one"]['exp_two'] = 'text';
$ARRAY_NAME["exp_one"]["exp_two"] =
"text";

any idea how build regexp for this?


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Re: PHP Array regexp.
country flaguser name
United States		 2007-07-31 10:22:20 
Try this

$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*)?3
]s*=s*(["'])(.*)
5s*;

It will place the desired values in groups 2 4 and 6 instead
of 1,2,3
because the quotes need to be in a capture group for
back-reference
matching.

On Jul 31, 8:24 am, KooT <Rafal...gmail.com> wrote:
> Hello,
>
> i need regexpresion that will match from this string:
> $ARRAY_NAME['exp_one']['exp_two'] = 'text';
>
> matches:
>  1 - exp_one
>  2 - exp_two
>  3 - text
>
> but sometimes in string can be 3 dimension array and
regexp should NOT
> match this:
>
> $ARRAY_NAME['exp_one']['exp_two']['exp_three'] =
'text';
>
> And another thing with quotes, it could be ' or "
:
>
> $ARRAY_NAME['exp_one']['exp_two'] = "text";
> $ARRAY_NAME["exp_one"]['exp_two'] = 'text';
> $ARRAY_NAME["exp_one"]["exp_two"] =
"text";
>
> any idea how build regexp for this?


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Re: PHP Array regexp.
country flaguser name
United States		 2007-07-31 14:48:02 
There was a mistake in my last post.  Here's the right
expression:
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*?)3
]s*=s*(["'])(.*)
5s*;

On Jul 31, 9:22 am, russ <black.russ...gmail.com> wrote:
> Try this
>
>
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*)?3
]s*=s*(["'])(.*)
> 5s*;
>
> It will place the desired values in groups 2 4 and 6
instead of 1,2,3
> because the quotes need to be in a capture group for
back-reference
> matching.
>
> On Jul 31, 8:24 am, KooT <Rafal...gmail.com> wrote:
>
> > Hello,
>
> > i need regexpresion that will match from this
string:
> > $ARRAY_NAME['exp_one']['exp_two'] = 'text';
>
> > matches:
> >  1 - exp_one
> >  2 - exp_two
> >  3 - text
>
> > but sometimes in string can be 3 dimension array
and regexp should NOT
> > match this:
>
> > $ARRAY_NAME['exp_one']['exp_two']['exp_three'] =
'text';
>
> > And another thing with quotes, it could be ' or
" :
>
> > $ARRAY_NAME['exp_one']['exp_two'] =
"text";
> > $ARRAY_NAME["exp_one"]['exp_two'] =
'text';
> >
$ARRAY_NAME["exp_one"]["exp_two"] =
"text";
>
> > any idea how build regexp for this?


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Re: PHP Array regexp.
country flaguser name
United States		 2007-07-31 16:02:26 
On 31 Lip, 21:48, russ <black.russ...gmail.com> wrote:
> There was a mistake in my last post.  Here's the right
expression:
>
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*?)3
]s*=s*(["'])(.*)
> 5s*;
>
Thank You very much for Your help. I have wrote some test
program i
perl, and its not working:

#!/usr/bin/perl

$string = "$TEST['blada']['marmolada'] = 'test'";
$string_false =
"$DUPA['blada']['marmolada']['czekolada'] =
'test'";

$string =~
/$TESTs*[(['"])(.*?)1]s*[(["'])(.*?)3]s*
=s*(["'])
(.*)5s*;/;
print( "1) Match 1: $1, match 2: $2, match 3:
$3n");

$string_false =~
/$TESTs*[(['"])(.*?)1]s*[(["'])(.*?)3]s*
=
s*(["'])(.*)s5s*;/;
print( "2) Match 1: $1, match 2: $2, match 3:
$3n");


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Re: PHP Array regexp.
country flaguser name
United States		 2007-07-31 16:22:42 
On 31 Lip, 21:48, russ <black.russ...gmail.com> wrote:
> There was a mistake in my last post.  Here's the right
expression:
>
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*?)3
]s*=s*(["'])(.*)
> 5s*;
>

Thanks a lot!
Its working!

Sample perl program to test it:

#!/usr/bin/perl

$string = "$TEST['blada']['marmolada'] =
'test';";
$string_false =
"$TEST['blada2']['marmolada2']['czekolada2'] =
'test';";


if($string =~
/$TESTs*[(['"])(.*?)1]s*[(["'])(.*?)3]s*
=
s*(["'])(.*)5s*;/)
{
        print( "1) Tested string: $stringn" );
        print( "1) Match 1: $1, match 2: $2, match 3:
$3, match 4: $4,
match 5: $5, match 6: $6n");
}
else
{
        print( "1) Not matchedn" );
}

if($string_false =~
/$TESTs*[(['"])(.*?)1]s*[(["'])(.*?)3]s*
=
s*(["'])(.*)s5s*;/)
{
        print( "2) Tested string: $string_falsen"
);
        print( "2) Match 1: $1, match 2: $2, match 3:
$3, match 4: $4,
match 5: $5, match 6: $6n");
}
else
{
        print( "2) Not matchedn");
}
--
RK


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Re: PHP Array regexp.
country flaguser name
United States		 2007-08-01 01:55:59 
On 31 Lip, 21:48, russ <black.russ...gmail.com> wrote:
> There was a mistake in my last post.  Here's the right
expression:
>
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*?)3
]s*=s*(["'])(.*)
> 5s*;


Strange. In perl its work fine but in PHP not.

string in $line:

$SERVICE_LANG['IMPREZY']['err_opis']['b']='Opisz
wydarzenie';

preg_match('/$SERVICE_LANGs*[(['"])(.*?)1]s*[([
"'])(.*?)3]
s*=s*(["'])(.*)5s*;/',$line,$matches)

matches array:

[0] => $SERVICE_LANG['IMPREZY']['err_opis']['b']='Opisz
wydarzenie';
[1] => '
[2] => IMPREZY
[3] => '
[4] => err_opis']['b
[5] => '
[6] => Opisz wydarzenie


4 element seems to be wrong :(


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Re: PHP Array regexp.
country flaguser name
United States		 2007-08-01 09:29:39 
Hi,

I changed the expression a bit.
#!/usr/bin/perl

$string = "$TEST['blada']['marmolada'] =
'test';";
$string_false =
"$TEST['blada2']['marmolada2']['czekolada2'] =
'test';";

if($string =~
/$TESTs*[['"]([^'"]+)['"]]s*[['"](
[^'"]+)['"]]s*
=s*['"]([^'"]+)['"];/)

{
        print( "1) Tested string: $stringn" );
        print( "1) Match 1: $1, match 2: $2, match 3:
$3, match 4: $4,
match 5: $5, match 6: $6n");
}

else
{
        print( "1) Not matchedn" );
}

if($string_false =~
/$TESTs*[['"]([^'"]+)['"]]s*[['"](
[^'"]+)['"]
]s*[['"]([^'"]+)['"]]s*=s*['"]([^
'"]+)['"];/)
{
        print( "2) Tested string: $string_falsen"
);
        print( "2) Match 1: $1, match 2: $2, match 3:
$3, match 4: $4,
match 5: $5, match 6: $6n");
}

else
{
        print( "2) Not matchedn");
}

The output reads:
1) Tested string: $TEST['blada']['marmolada'] = 'test';
1) Match 1: blada, match 2: marmolada, match 3: test, match
4: ,
match 5: , match 6:
2) Tested string:
$TEST['blada2']['marmolada2']['czekolada2'] =
'test';
2) Match 1: blada2, match 2: marmolada2, match 3:
czekolada2, match 4:
test,
match 5: , match 6:

To match each exp_one, I have used: ['exp_one']
s*[['"]([^'"]+)['"]]
s*
To match 'text', I have used:      
['"]([^'"]+)['"]

I avoid using the .* to do a non-greedy match in your
expression.
Do let me know if this works in PHP.

Thanks
Syd
P.S. Must read "Mastering Regular Expressions - Jeffrey
Friedl"

On Aug 1, 11:55 am, KooT <Rafal...gmail.com> wrote:
> On 31 Lip, 21:48, russ <black.russ...gmail.com> wrote:
>
> > There was a mistake in my last post.  Here's the
right expression:
> >
$ARRAY_NAMEs*[(['"])(.*?)1]s*[(["'])(.*?)3
]s*=s*(["'])(.*)
> > 5s*;
>
> Strange. In perl its work fine but in PHP not.
>
> string in $line:
>
> $SERVICE_LANG['IMPREZY']['err_opis']['b']='Opisz
wydarzenie';
>
>
preg_match('/$SERVICE_LANGs*[(['"])(.*?)1]s*[([
"'])(.*?)3]
> s*=s*(["'])(.*)5s*;/',$line,$matches)
>
> matches array:
>
> [0] =>
$SERVICE_LANG['IMPREZY']['err_opis']['b']='Opisz
wydarzenie';
> [1] => '
> [2] => IMPREZY
> [3] => '
> [4] => err_opis']['b
> [5] => '
> [6] => Opisz wydarzenie
>
> 4 element seems to be wrong :(


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Re: PHP Array regexp.
country flaguser name
United States		 2007-08-06 08:03:27 


On 1 Sie, 16:29, "sydc...gmail.com"
<sydc...gmail.com> wrote:
[...]
> Do let me know if this works in PHP.

Yes, its working. Thank You a lot for Your help! 

> P.S. Must read "Mastering Regular Expressions -
Jeffrey Friedl"

I will read it, thanks!

--
RK


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Re: PHP Array regexp.
country flaguser name
United States		 2007-08-07 14:39:31 
> To match 'text', I have used:      
['"]([^'"]+)['"]

Helo again 

What if in text is 'sdsd'sdsdsd', or
"erer"rerer" ?

$ARRAY['one']['two'] = 'www'wwww';
$ARRAY['one']['two'] = "www"wwww";

What is the best regexp for this?

--
RK


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Re: PHP Array regexp.
country flaguser name
United States		 2007-08-07 15:08:44 
There are a couple of adjustments you can make.  The first
one is to
change the last ['"] to be a back reference, otherwise
you won't match
['this"]correctly']

Here's the Java regex way to do back references

(['"])(.*?)1

Now to handle escaped quotes, you can do a negative
look-behind like
this (Again, the is a Java regex, perl probably has a
different
syntax)

(['"])(.*?)1(?<!\['"])

This will handle

["stuff"like'this"]

But it won't handle
["this\"]
because of the two back slashes.

You're beginning to reach the limits of what a regex can do
at this
point.


On Aug 7, 1:39 pm, KooT <Rafal...gmail.com> wrote:
> > To match 'text', I have used:      
['"]([^'"]+)['"]
>
> Helo again 
>
> What if in text is 'sdsd'sdsdsd', or
"erer"rerer" ?
>
> $ARRAY['one']['two'] = 'www'wwww';
> $ARRAY['one']['two'] = "www"wwww";
>
> What is the best regexp for this?
>
> --
> RK


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