it is logically impossible b/c u want to return a piece of
text that
originally wasn't present in the text u r processing. This
operation
requires additional modification/string processing that
recuires more
code aside from pure regex.
On Aug 17, 8:53 am, "Brian E. Dunbar"
<bdun... dunbarconsulting.org>
wrote:
> Thanks. Unfortunately, I don't have the luxury of
concatenating the two
> capture groups. I need the value returned in a single
capture group.
>
>
>
> -----Original Message-----
> From: regexgooglegroups.com [mailto:regexgooglegroups.com]On Behalf Of
>
> Sergei Z
> Sent: Thursday, August 16, 2007 9:27 PM
> To: Regex
> Subject: Re: Leave something out of a capturing group
>
> if u use
>
> (?:(He)ll(o))
>
> then group #1 will return *He*
> and group #2 will return *o*
>
> and u cannot really split the whole match *hello* [i.e.
group #0] ,
> it'll be there anyway.
>
> On Aug 14, 5:17 pm, brian <bdun...dunbarconsulting.org> wrote:
> > I am trying to match a string and leave part of
the match out of the
> > matching group. For example:
>
> > Source String:
>
> > Hi Hello Hi
>
> > Regex that almost does what I want:
>
> > .*(He(?:ll)o).*
>
> > $1 returns "Hello" and what I want is
"Heo", with the two l's removed
> > corresponding to the non-capturing group.
>
> > Is what I want doable?
>
> > Thanks- Hide quoted text -
>
> - Show quoted text -
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