Replace ,_,_,_ ... ,

Hello,

I'm looking for an RegEx which replaces
  <Word>,_<Pattern0>,_<Pattern1>,_ ...
,<PatternN>
with
<Word> <Pattern0> Literal <Word>
<Pattern1> Literal ... <Word>
<PatternN>

Word is just a single word (not a literal)
,_ is a delimiter (just a ',' and optionally Spaces), not so
important
<Pattern0> ... <PatternN> are always the same
patterns.
Literal is always the same.

Main problem is the correct grouping for the
backreferences.


Thanks and greetings
Udo


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This is not possible to my knowledge.  The problem is as you
say with
the back references.  If you have the following expression

(.)*

and then match it against string

abcde

then back reference 1 will be 'e'.  All previous back
references are
lost.



On Aug 31, 4:58 pm, Udo <WeikEng...aol.com> wrote:
> Hello,
>
> I'm looking for an RegEx which replaces
>   <Word>,_<Pattern0>,_<Pattern1>,_
... ,<PatternN>
> with
> <Word> <Pattern0> Literal <Word>
<Pattern1> Literal ... <Word>
> <PatternN>
>
> Word is just a single word (not a literal)
> ,_ is a delimiter (just a ',' and optionally Spaces),
not so important
> <Pattern0> ... <PatternN> are always the
same patterns.
> Literal is always the same.
>
> Main problem is the correct grouping for the
backreferences.
>
> Thanks and greetings
> Udo


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Hi Udo,

Please try this approach.

Source:
<Word>,_<Pattern0>,_<Pattern1>,_ ...
,<PatternN>
Pattern:
([^,_]+),_([^,_]+),_([^,_]+),_([^,_]+)
Results:
Match <Word>,_<Pattern0>,_<Pattern1>,_ ...
 <Word> <Pattern0>
<Pattern1> ...
$1  <Word>
$2  <Pattern0>
$3  <Pattern1>

Thanks
Syd





On Sep 1, 4:02 am, russ <black.russ...gmail.com> wrote:
> This is not possible to my knowledge.  The problem is
as you say with
> the back references.  If you have the following
expression
>
> (.)*
>
> and then match it against string
>
> abcde
>
> then back reference 1 will be 'e'.  All previous back
references are
> lost.
>
> On Aug 31, 4:58 pm, Udo <WeikEng...aol.com> wrote:
>
>
>
> > Hello,
>
> > I'm looking for an RegEx which replaces
> >  
<Word>,_<Pattern0>,_<Pattern1>,_ ...
,<PatternN>
> > with
> > <Word> <Pattern0> Literal <Word>
<Pattern1> Literal ... <Word>
> > <PatternN>
>
> > Word is just a single word (not a literal)
> > ,_ is a delimiter (just a ',' and optionally
Spaces), not so important
> > <Pattern0> ... <PatternN> are always
the same patterns.
> > Literal is always the same.
>
> > Main problem is the correct grouping for the
backreferences.
>
> > Thanks and greetings
> > Udo- Hide quoted text -
>
> - Show quoted text -


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