Re: extract all numbers from a long string

On Oct 31, 8:31 am, Jeff <jeff.hill...gmail.com> wrote:
> Pattern: "^(d+)w*s*(.*)$"
> Replacement: "$2#$1"
>
> This assumes you are operating on each string, one at a
time.  The
> first set of parentheses captures the number at the
beginning of the
> string.  The "th", "st",
"nd", etc. and any white space is then
> matched, but not captured.  The second set of
parentheses captures
> everything else.  The replacement string is just the
second capture, a
> "#", and then the first capture.
>
> I hope this helps.
>
> Jeff
>



Hi Jeff,
Thanks a million for the help - I really appreciate it. It's
very
close to working now - I just need to tweak the pattern to
catch all
the numbers in the string regardless of where they are
positioned. Is
that possible?
for example:

31st Sutton Coldfield (3rd Streetly)
returns
Sutton Coldfield (Streetly)#31#3

Thanks again!
Ciarán


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On Nov 5, 8:55 am, Ciaran <cronok...hotmail.com> wrote:
> On Oct 31, 8:31 am, Jeff <jeff.hill...gmail.com> wrote:
>
> > Pattern: "^(d+)w*s*(.*)$"
> > Replacement: "$2#$1"
>
> > This assumes you are operating on each string, one
at a time.  The
> > first set of parentheses captures the number at
the beginning of the
> > string.  The "th", "st",
"nd", etc. and any white space is then
> > matched, but not captured.  The second set of
parentheses captures
> > everything else.  The replacement string is just
the second capture, a
> > "#", and then the first capture.
>
> > I hope this helps.
>
> > Jeff
>
> Hi Jeff,
> Thanks a million for the help - I really appreciate it.
It's very
> close to working now - I just need to tweak the pattern
to catch all
> the numbers in the string regardless of where they are
positioned. Is
> that possible?
> for example:
>
> 31st Sutton Coldfield (3rd Streetly)
> returns
> Sutton Coldfield (Streetly)#31#3
>
> Thanks again!
> Ciarán

I'm sorry I missed the fact that position isn't important. 
One way to
do this is to use the count parameter of the preg_replace
function:

$count = 0;

do
{

   $string = preg_replace(
"^(.*?)(d+)[a-z]+s+(.*?)$",
                           "$1$3#$2",
                           $string, -1, $count );
}
while ( $count > 0 );

Good luck.

Jeff


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