how to get a directory's "full" name?

On Fri, 12 May 2006, Paul D. Smith wrote:

> %% "Aditya Kher" <aditya.khergmail.com> writes:
>
>   >> cd to arg, then echo full dir name.  is
there a simpler or built-in
>   >> way that's better?
>
>   ak> the unix command dirname gives the directory
name
>   ak> see also basename for getting file name in a
similar manner
>
> dirname and basename are simply string munchers: they
break up
> strings on "/" etc.  They do NOT evaluate
their arguments to find
> fully-qualified pathnames.
>
> In addition, the make functions $(dir ...), $(notdir
...),
> $(basename ...), etc. are much better/faster for this
kind of thing,
> as long as you don't need to work on a shell variable.

actually, i'm pretty sure that's *exactly* what i need to
do.  in the
context of your multi-arch build, i want the user to be able
to
specify the build directory, not based on that funky
calculation of
yours, but with a directory name of any acceptable format:

  $ make BUILDDIR=/tmp
  $ make BUILDDIR=subdir       (relative to where i am now)
  $ make BUILDDIR=s1/../s2/../s3

and have all of those work.  i'll take a look at those make
functions
but i know that at least i can do it with that hacky macro i
posted
earlier.  speed is not a critical factor here.

rday


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