Quick question on awk usage

Sorry, $14 == 528, not $12 (looks like the email client
wrapped the line
also)

Aaron 

-----Original Message-----
From: redhat-list-bouncesredhat.com
[mailto:redhat-list-bouncesredhat.com] On Behalf Of
Bliss, Aaron
Sent: Tuesday, June 27, 2006 11:01 AM
To: redhat-listredhat.com
Subject: Quick question on awk usage

Hi everyone, I have a quick question on using awk from the
command line;
I have a tab delimited file, and would like to know the
syntax to print
the entire line only when $12 == 575; the syntax from the
command line
to print only $1 would be cat security.log | awk '{print
$1}' ; any
ideas (grepping for 578 won't be good enough since it's
possible that
578 could appear somewhere else in the file)  Thanks very
much.

Aaron

Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 
    4
Security        263985  Sun Jun 25 15:54:02 2006        528
Jun 25 15:54:02 ms-unix-s02.preferredcare.org MSWinEventLog 
    4
Security        263985  Sun Jun 25 15:54:02 2006        575 
        


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> -----Original Message-----
> From: redhat-list-bouncesredhat.com 
> [mailto:redhat-list-bouncesredhat.com] On Behalf Of
Bliss, Aaron
> Sent: Tuesday, June 27, 2006 11:03 AM
> To: redhat-listredhat.com
> Subject: RE: Quick question on awk usage
> 
> Sorry, $14 == 528, not $12 (looks like the email client

> wrapped the line
> also)
> 
> Aaron 
> 
> Hi everyone, I have a quick question on using awk from
the 
> command line; I have a tab delimited file, and would
like to 
> know the syntax to print the entire line only when $12
== 
> 575; the syntax from the command line to print only $1
would 
> be cat security.log | awk '{print $1}' ; any ideas
(grepping 
> for 578 won't be good enough since it's possible that
> 578 could appear somewhere else in the file)  Thanks
very much.
> 
> Aaron
> 
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org
MSWinEventLog      4
> Security        263985  Sun Jun 25 15:54:02 2006       
528
> Jun 25 15:54:02 ms-unix-s02.preferredcare.org
MSWinEventLog      4
> Security        263985  Sun Jun 25 15:54:02 2006       
575          
> 
> 

I believe this should do it:

awk ' $14 == 575 {print $0}'

Michael

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