class instead of id

Hi,
I'm building an application and I need that for example,
the
"slideshow" at:
   new GFslideShow(samples, "slideshow",
options);
will refer to a class. I saw it was not working for a
class.
Is there any way to do it? (using id won't be xhtml valid
since it is
a repeatable pattern.)
I know sometimes you can do "div.slideshow" but it
did not work as
well.
Thanks.
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Because there is no getElementsByClassName() functionality
in the W3C
DOM, the only way to do this would be to write your own
loop, as
follows:

var a=document.getElementsByTagName('*');
var slideshows=[];
for(var b=0;b<a.length;b++){
 if(a[b].className.match(/b?
THE_CLASS_OF_THOSE_ELEMENTS_YOU_WANT_TO_BE_SLIDESHOWSb?/)){
// Make
sure to leave the b?'s
  slideshows.push(new GFslideShow(samples,a[b],options));
 }
}

Or you could rearrange that to make your own
getElementsByClassName
function:

function getElementsByClassName(className){
 var a=document.getElementsByTagName('*');
 var b=[];
 for(var c=0;c<a.length;c++){
  var d=new
RegExp("b?"+className+"b?")
  if(a[c].className.match(d)){b.push(a[c]);}
 }
 return b;
}
function initSlideshows(className){
 var a=getElementsByClassName(className);
 window.slideshows=[];
 for(var b=0;b<a.length;b++){
  window.slideshows.push(new
GFslideShow(samples,a[b],options));
 }
}

Jeremy R. Geerdes
Effective website design & development
Des Moines, IA

For more information or a project quote:
http://jgeerdes.home.m
chsi.com
jgeerdesmchsi.com
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Thanks a lot,
But probably I don't put any of the two options correctly.
I'll appreciate if you could help me implementing it here:

<script type="text/javascript">
    function load() {
      var samples = "[CUSTOM:rss]";
      var options = {
        displayTime: 3000,
    thumbnailSize : GFslideShow.THUMBNAILS_MEDIUM,
        transistionTime: 600

      };
      new GFslideShow(samples, "slideshow",
options);

    }
    google.load("feeds", "1");
    google.setOnLoadCallback(load);
  </script>
<div
class="slideshow">Loading...</div>


On Dec 30, 1:25 pm, "jgeerdes [AJAX APIs
"Guru"]"
<jgeer...mchsi.com> wrote:
> Because there is no getElementsByClassName()
functionality in the W3C
> DOM, the only way to do this would be to write your own
loop, as
> follows:
>
> var a=document.getElementsByTagName('*');
> var slideshows=[];
> for(var b=0;b<a.length;b++){
>  if(a[b].className.match(/b?
>
THE_CLASS_OF_THOSE_ELEMENTS_YOU_WANT_TO_BE_SLIDESHOWSb?/)){
// Make
> sure to leave the b?'s
>   slideshows.push(new
GFslideShow(samples,a[b],options));
>  }
>
> }
>
> Or you could rearrange that to make your own
getElementsByClassName
> function:
>
> function getElementsByClassName(className){
>  var a=document.getElementsByTagName('*');
>  var b=[];
>  for(var c=0;c<a.length;c++){
>   var d=new
RegExp("b?"+className+"b?")
>   if(a[c].className.match(d)){b.push(a[c]);}
>  }
>  return b;}
>
> function initSlideshows(className){
>  var a=getElementsByClassName(className);
>  window.slideshows=[];
>  for(var b=0;b<a.length;b++){
>   window.slideshows.push(new
GFslideShow(samples,a[b],options));
>  }
>
> }
>
> Jeremy R. Geerdes
> Effective website design & development
> Des Moines, IA
>
> For more information or a project quote:http://jgeerdes.home.m
chsi.com
> jgeer...mchsi.com
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Jeremy,
I've sent you an email.
Thanks.

On Dec 30, 8:37 pm, aviavia <googleale...nukedesigners.com> wrote:
> Thanks a lot,
> But probably I don't put any of the two options
correctly.
> I'll appreciate if you could help me implementing it
here:
>
> <script type="text/javascript">
>     function load() {
>       var samples = "[CUSTOM:rss]";
>       var options = {
>         displayTime: 3000,
>     thumbnailSize : GFslideShow.THUMBNAILS_MEDIUM,
>         transistionTime: 600
>
>       };
>       new GFslideShow(samples, "slideshow",
options);
>
>     }
>     google.load("feeds", "1");
>     google.setOnLoadCallback(load);
>   </script>
> <div
class="slideshow">Loading...</div>
>
> On Dec 30, 1:25 pm, "jgeerdes [AJAX APIs
"Guru"]"
>
> <jgeer...mchsi.com> wrote:
> > Because there is no getElementsByClassName()
functionality in the W3C
> > DOM, the only way to do this would be to write
your own loop, as
> > follows:
>
> > var a=document.getElementsByTagName('*');
> > var slideshows=[];
> > for(var b=0;b<a.length;b++){
> >  if(a[b].className.match(/b?
> >
THE_CLASS_OF_THOSE_ELEMENTS_YOU_WANT_TO_BE_SLIDESHOWSb?/)){
// Make
> > sure to leave the b?'s
> >   slideshows.push(new
GFslideShow(samples,a[b],options));
> >  }
>
> > }
>
> > Or you could rearrange that to make your own
getElementsByClassName
> > function:
>
> > function getElementsByClassName(className){
> >  var a=document.getElementsByTagName('*');
> >  var b=[];
> >  for(var c=0;c<a.length;c++){
> >   var d=new
RegExp("b?"+className+"b?")
> >   if(a[c].className.match(d)){b.push(a[c]);}
> >  }
> >  return b;}
>
> > function initSlideshows(className){
> >  var a=getElementsByClassName(className);
> >  window.slideshows=[];
> >  for(var b=0;b<a.length;b++){
> >   window.slideshows.push(new
GFslideShow(samples,a[b],options));
> >  }
>
> > }
>
> > Jeremy R. Geerdes
> > Effective website design & development
> > Des Moines, IA
>
> > For more information or a project quote:http://jgeerdes.home.m
chsi.com
> > jgeer...mchsi.com
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Hi Jeremy,
I apologize for the misunderstanding.
Did you get the other emails from me containing the correct
link?
Thanks Avi.


On Dec 30 2007, 11:38 pm, aviavia <googleale...nukedesigners.com>
wrote:
> Jeremy,
> I've sent you an email.
> Thanks.
>
> On Dec 30, 8:37 pm, aviavia <googleale...nukedesigners.com> wrote:
>
> > Thanks a lot,
> > But probably I don't put any of the two options
correctly.
> > I'll appreciate if you could help me implementing
it here:
>
> > <script type="text/javascript">
> >     function load() {
> >       var samples = "[CUSTOM:rss]";
> >       var options = {
> >         displayTime: 3000,
> >     thumbnailSize :
GFslideShow.THUMBNAILS_MEDIUM,
> >         transistionTime: 600
>
> >       };
> >       new GFslideShow(samples,
"slideshow", options);
>
> >     }
> >     google.load("feeds",
"1");
> >     google.setOnLoadCallback(load);
> >   </script>
> > <div
class="slideshow">Loading...</div>
>
> > On Dec 30, 1:25 pm, "jgeerdes [AJAX APIs
"Guru"]"
>
> > <jgeer...mchsi.com> wrote:
> > > Because there is no getElementsByClassName()
functionality in the W3C
> > > DOM, the only way to do this would be to
write your own loop, as
> > > follows:
>
> > > var a=document.getElementsByTagName('*');
> > > var slideshows=[];
> > > for(var b=0;b<a.length;b++){
> > >  if(a[b].className.match(/b?
> > >
THE_CLASS_OF_THOSE_ELEMENTS_YOU_WANT_TO_BE_SLIDESHOWSb?/)){
// Make
> > > sure to leave the b?'s
> > >   slideshows.push(new
GFslideShow(samples,a[b],options));
> > >  }
>
> > > }
>
> > > Or you could rearrange that to make your own
getElementsByClassName
> > > function:
>
> > > function getElementsByClassName(className){
> > >  var a=document.getElementsByTagName('*');
> > >  var b=[];
> > >  for(var c=0;c<a.length;c++){
> > >   var d=new
RegExp("b?"+className+"b?")
> > >   if(a[c].className.match(d)){b.push(a[c]);}
> > >  }
> > >  return b;}
>
> > > function initSlideshows(className){
> > >  var a=getElementsByClassName(className);
> > >  window.slideshows=[];
> > >  for(var b=0;b<a.length;b++){
> > >   window.slideshows.push(new
GFslideShow(samples,a[b],options));
> > >  }
>
> > > }
>
> > > Jeremy R. Geerdes
> > > Effective website design & development
> > > Des Moines, IA
>
> > > For more information or a project quote:http://jgeerdes.home.m
chsi.com
> > > jgeer...mchsi.com
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