That makes sense, but it's still not giving me the behavior
I'm
expecting...here are some examples:
http://test.fend
errhodes.org/arc.php
The 5th & 6th numbers seem to determine the relative
size & skew of the
arc compared to a circle (setting one of the values to 0 or
leaving the
6th number out altogether gives you a straight line). I
also tried
adding 7th & 8th numbers thinking they might be flags
similar to the
command-line syntax, or that maybe the angle values belong
in that
position...but apparently they turn the arc into a polygon!
Timothy Hunter wrote:
> If PerlMagick is anything like RMagick (and I have no
reason to believe
> it isn't), then the first two pairs of numbers are the
coordinates of a
> rectangle that bounds the arc. The 5th number is the
angle in degrees
> where the arc should start (0 degrees is at 3 o'clock)
and the 6th
> number is the angle in degrees where the arc should
end. Here's an
> example for the arc defined by (40, 50, 250,180,
0,270).
>
> Hope this helps!
>
>
>
>
>
> On Feb 22, 2006, at 10:40 AM, James Garfield wrote:
>
>> I'm trying to figure out how the
"points" string passed to the
>> PerlMagick Draw() method affects the drawing of an
ImageMagick arc:
>>
>> $image->Draw(
>> stroke => 'black',
>> fill => 'white',
>> primitive => 'arc',
>> points => '150,100 100,50 1,1',
>> strokewidth => 2
>> );
>>
>> So far all I've got is that the first two pairs
are the start & end
>> coordinates. What are the other values that are
supposed to follow,
>> i.e. to shape & scale the arc?
>> _______________________________________________
>> Magick-users mailing list
>> Magick-users imagemagick.org
>> http://studio.imagemagick.org/mailman/listinfo/magick
-users
>
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