New bug, or new feature?

Many months ago blocks were made non-activatable by default. Methods still activate by default, but blocks don't. It's annoying, isn't it?

On 12-Dec-06, at 3:16 AM, Jon Kleiser wrote:

When I use Io-2006-12-07 (which presents itself as Io 20061114 in my 

PPC Mac terminal window), I can do the following:

Io> b := block(x, (x+2) println)

==> block(x, (x +(2)) println)

Io> b(8)

==> block(x, (x +(2)) println)

Io> m := method(x, (x+2) println)

==> method(x, (x +(2)) println)

Io> m(8)

10

==> 10

As you can see, when I try to execute b(8), I only get the block b 

back, no execution. I guess this is a bug.

When I do the same with a method, it works like in the old days.

/Jon

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Jeremy Tregunna

jtregunnablurgle.ca">jtregunnablurgle.ca

As long as I know that I have do "b call(8)&quot; instead of "b(8)", it's
not that bad. Of course there should have been a few words about this
feature in the docs, but I found nothing. I found some postings about
"activatable&quot; on the list around the middle of July, but I didn't
find the "final declaration" or anything about the reason for this
feature.

/Jon

>Many months ago blocks were made non-activatable by default. Methods
>still activate by default, but blocks don't. It's annoying, isn't it?
>
>On 12-Dec-06, at 3:16 AM, Jon Kleiser wrote:
&gt;
>>;When I use Io-2006-12-07 (which presents itself as Io 20061114 in my
>&gt;PPC Mac terminal window), I can do the following:
>>
>>Io> b := block(x, (x+2) println)
>>
&gt;>==&gt; block(x, (x +(2)) println)
>>Io&gt; b(8)
>>
>&gt;==> block(x, (x +(2)) println)
>>Io&gt; m := method(x, (x+2) println)
>>
&gt;>==&gt; method(x, (x +(2)) println)
>>Io&gt; m(8)
>>10
>;>
>>==> 10
>&gt;
>>;As you can see, when I try to execute b(8), I only get the block b
>>;back, no execution. I guess this is a bug.
>>When I do the same with a method, it works like in the old days.
>;>
>>/Jon
...
>Jeremy Tregunna