Maybe I'm missing something here.
At step 5, when FA restarts, why is the advertisement sent
with sequence
number 6? Wouldn't it be 1?
The window when this error can happen is that FA sends
advertisement
with seq num 1, restarts and again sends aa with seq num =1.
Then the
two are AAs have equal seq num and MN will not register. I
think in any
other case, restart would not cause a problem.
Regards,
Arun
-----Original Message-----
From: Ahmad Muhanna [mailto:amuhanna nortel.com]
Sent: Friday, March 23, 2007 3:46 PM
To: Bjorn Andersson
Cc: mip4 ietf.org
Subject: RE: [Mip4] Minor issue with MN advertisement
sequence number
handling
Now I understand what you meant by "If the FA is
restarted before it has
sent a second advertisement"
I also agree that this case is very unlikely.
Regards,
Ahmad
> -----Original Message-----
> From: bjondersson gmail.com [mailto:bjondersson gmail.com] On Behalf
> Of Bjorn Andersson
> Sent: Friday, March 23, 2007 8:27 AM
> To: Muhanna, Ahmad (RICH1:2H10)
> Cc: mip4 ietf.org
> Subject: Re: [Mip4] Minor issue with MN advertisement
sequence number
> handling
>
> On 3/23/07, Ahmad Muhanna <amuhanna nortel.com> wrote:
> > Bjorn Andersson [mailto:bjorn iki.fi]:
> > > If the FA is restarted before it has sent a
second
> advertisement the
> > > MN will not reregister.
> >
> > Why? Can you please explain.
>
> 1. FA starts
> 2. FA sends advertisement with sequence number 0 3. MN
registers via
> FA 4. FA restarts 5. FA sends advertisement with
sequence number 0 6.
> Sequence number is equal to, not less than, previous
sequence number.
> MN does not register.
> 7. MN sends packet to FA for tunneling, but MN is not
registered to FA
> (since the FA restarted after the registration), so the
FA does not
> tunnel the packet to the HA. This will be the case
until the
> registration expires.
>
> But as I said, it is minor issues since it quite
unlikely to occur,
> but it could still be improved and fixed in the RFC.
> Or am I missing something?
>
> Bjorn
>
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