shell question...

Jukka Salmi wrote:
[ ... ]
> 	[1] 6980
> 
> I guess it's the shell who prints these strings, isn't
it? If yes, is
> there a way to suppress this output?

Yes, it is the shell that produces that output.

You can suppress the output by having the process
disassociate itself from the
shell's process group and tty.  Most daemons will do so
automaticly (see "man 3
daemon", "man 8 daemon"), and some shells
have a "disown" primitive which will
disown a backgrounded task.

-- 
-Chuck

Chuck Swiger --> netbsd-help (2006-01-31 10:53:15 -0500):
> Jukka Salmi wrote:
> [ ... ]
> > 	[1] 6980
> > 
> > I guess it's the shell who prints these strings,
isn't it? If yes, is
> > there a way to suppress this output?
> 
> Yes, it is the shell that produces that output.
> 
> You can suppress the output by having the process
disassociate itself from the
> shell's process group and tty.  Most daemons will do so
automaticly (see "man 3
> daemon", "man 8 daemon"), and some
shells have a "disown" primitive which will
> disown a backgrounded task.

I see. Hmm, the program I want to run in the background is
itself a
shell script, and the shell doesn't seem to have such a
disown
primitive.

Is it possible to do something like daemon(3) in shell? I
tried with
putting

	cd /
	exec <&-
	exec >&-
	exec 2>&-

to the top of my script, but this seems not to be enough...


Regards, Jukka

-- 
bashian roulette:
$ ((RANDOM%6)) || rm -rf ~