Birgit Kellner wrote:
> Vaclav Barta schrieb:
>
>> On Friday 20 July 2007 20:27, Birgit Kellner
wrote:
>>
>>
>>> Petr Pajas schrieb:
>>>
>>>
>>>> First of all, why do you do that "by
hand"? To get all text nodes
>>>> from a subtree nicely concatenated, you can
use e.g.
>>>>
>>>> $text = $node->findvalue('string(.)')
>>>>
>>>>
>>> I should have been more specific on that. I'm
not interested in all text
>>> nodes, but in text node children of the element
<seg>, and in text node
>>>
>>>
>> seg/text()
>>
>>
>>
>>> children of the element <span> that can
be contained within <seg>. <seg>
>>>
>>>
>> seg/span/text()
>>
>> XPath may not be very perlish, but it's quite
useful...
>>
>> Bye
>> Vasek
>>
>>
>>
> Yes, but that wouldn't get me the proper sequence, no?
>
> Consider:
>
> <seg>This is <span>a cold
breeze</span><note>Oh, and here's some text
> which deals with a completely different subject-matter,
say, bunny
> rabbits on a balcony.</note> on an unbearably hot
summer evening.</seg>
>
Assuming that $seg contains a reference to the
"seg" node in the example
above:
my $seg_text = '';
for my $node ($seg->findnodes('text() | span'))
{
$seg_text .= $node->findvalue('string(.)');
}
will produce "This is a cold breeze on an unbearably
hot summer
evening." Is this what you are trying to achieve (or
at least steer
you in the right direction)?
FYI, the 'text() | span' XPath expression above selects just
the raw
text node and "span" element children of the
"seg" element, skipping the
"note" element children (or any other child nodes,
for that matter). By
combining the two separate relative XPaths
"text()" and "span" with an
or operator, findnodes() will return all the nodes in the
proper
sequence. Then, as Petr suggested, findvalue('string(.)')
will return
the concatenated text of the current node and any of its
descendants.
HTH,
Richard
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