You cannot simply subtract or add month VARs using mktime to
obtain previous or next months as suggested in previous user
comments (at least not with a DD > 28 anyway).
If the date is 03-31-2007, the following yeilds March as a
previous month. Not what you wanted.
<?php
$dateMinusOneMonth = mktime(0, 0, 0, (3-1), 31, 2007 );
$lastmonth = date("n | F", $dateMinusOneMonth);
echo $lastmonth; //---> 3 | March
?>
mktime correctly gives you back the 3rd of March if you
subtract 1 month from March 31 (there are only 28 days in
Feb 07).
If you are just looking to do month and year arithmetic
using mktime, you can use general days like 1 or 28 to do
stuff like this:
<?php
$d_daysinmonth = date('t',
mktime(0,0,0,$myMonth,1,$myYear)); // how many days in
month
$d_year = date('Y', mktime(0,0,0,$myMonth,1,$myYear)); //
year
$d_isleapyear = date('L',
mktime(0,0,0,$myMonth,1,$myYear)); // is YYYY a leapyear?
$d_firstdow = date('w', mktime(0,0,0,$myMonth,'1',$myYear));
// FIRST falls on what day of week (0-6)
$d_firstname = date('l',
mktime(0,0,0,$myMonth,'1',$myYear)); // FIRST falls on what
day of week Full Name
$d_month = date('n', mktime(0,0,0,$myMonth,28,$myYear));
// month of year (1-12)
$d_monthname = date('F', mktime(0,0,0,$myMonth,28,$myYear));
// Month Long name (July)
$d_month_previous = date('n',
mktime(0,0,0,($myMonth-1),28,$myYear)); // PREVIOUS month
of year (1-12)
$d_monthname_previous = date('F',
mktime(0,0,0,($myMonth-1),28,$myYear)); // PREVIOUS Month
Long name (July)
$d_month_next = date('n',
mktime(0,0,0,($myMonth+1),28,$myYear)); // NEXT month of
year (1-12)
$d_monthname_next = date('F',
mktime(0,0,0,($myMonth+1),28,$myYear)); // NEXT Month Long
name (July)
$d_year_previous = date('Y',
mktime(0,0,0,$myMonth,28,($myYear-1))); // PREVIOUS year
$d_year_next = date('Y',
mktime(0,0,0,$myMonth,28,($myYear+1))); // NEXT year
$d_weeksleft = (52 - $d_weekofyear); // how many weeks
left in year
$d_daysinyear = $d_isleapyear ? 366 : 365; // set correct
days in year for leap years
$d_daysleft = ($d_daysinyear - $d_dayofyear); // how many
days left in year
?>
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