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Thread: a question about boost python
a question about boost python
user name
 2007-10-16 04:23:13 

  


  

    


Hi All



I have a set of functions which last parameters are out-parameter. i.e.



  void  function1(int  t1, float t2, string& t3) ;



I want to expose these functions in python, but such definition (~def(“function1”, function1)~) is not what I want.



Because we have to write python code like this:



   strTest=’’



   function1(1,2.0,strTest);



I prefer to writing python code like this




   strTest = funciton1(1,2.0)



Is there any idea to solve this question?



Thanks












  

  
  
   
     
    

  

    Re:  a question about boost python
  


  

     user name

     2007-10-16 05:23:55
  


  

    

  


  

    On 10/16/07, Chang Chen < Chang_Chensonic.com">Chang_Chensonic.com> wrote:













Hi All



I have a set of
 functions which last parameters are out-
pa
rameter. i.e.




  void
  function1(int
  t1,
 float 
t2, string
& t3) 
;



I want to expose
 these functions in python, but such defi
nition
 (~d
ef("function1
", function1)
~) is not what I
 want.



Because 
we have to write python 
code like this:



 &nbsp; strTest=
''



 &nbsp; function1(1,2.0,strTest);




I prefer to writing python
 code like this




 &nbsp; strTest = funciton1(1,2.0)



Is there any idea to solve this question?


In short: to create another function, with the desired interface. In your case you just don't have other choice - std::string is mapped to Python string, which is immutable.

Read more here: 
http://language-binding.net/pyplusplus/documentation/functions/transformation/built_in/output.html

-- 
Roman Yakovenko
C++ Python language binding

http://www.language-binding.net/


  

  
  
   
     
    






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