Ajax way

Hi,

I want to return json from an action, but I have hard times
finding out
how to do it the best way with ZF. For the moment I do:

	function updateorderAction() {
		$i = 1;
		$o_divisiontable = new Division();
		foreach($_POST['divisioncontainer'] AS $i_divisionid) {
			$o_division =
$o_divisiontable->fetchRow("division_id =
$i_divisionid");
			$o_division->priority = $i;
			$o_division->save();
			$i++;
		}
		$a_return = array("result", 1);
		echo json_encode($a_return);
		die;
	}

But that isn't the way, is it?

/Peter

Peter,

This may not be the most correct way, but this is the
solution I use:

Zend_Loader::loadClass('Zend_Json');
$this->_response->setHeader('content-type',
'application/json', true);
$this->_response->setBody("/*-secure-n" .
Zend_Json::encode($response) .
"n*/");

$response really can be anything, a string, an array, an
object.

Cheers,
Steven

-----Original Message-----
From: Peter Lauri [mailto:peterlaurigmail.com] 
Sent: Monday, 26 November 2007 7:17 AM
To: Zend Framework General
Subject: [fw-general] Ajax way

Hi,

I want to return json from an action, but I have hard times
finding out
how to do it the best way with ZF. For the moment I do:

	function updateorderAction() {
		$i = 1;
		$o_divisiontable = new Division();
		foreach($_POST['divisioncontainer'] AS $i_divisionid) {
			$o_division =
$o_divisiontable->fetchRow("division_id =
$i_divisionid");
			$o_division->priority = $i;
			$o_division->save();
			$i++;
		}
		$a_return = array("result", 1);
		echo json_encode($a_return);
		die;
	}

But that isn't the way, is it?

/Peter

But the problem is I am getting "edit.phtml" not
found if I don't "die"
the action. Or will this change if I do the setHeader
content-type?

/Peter



On Mon, 2007-11-26 at 07:45 +1000, Steven Brown wrote:
> Peter,
> 
> This may not be the most correct way, but this is the
solution I use:
> 
> Zend_Loader::loadClass('Zend_Json');
> $this->_response->setHeader('content-type',
'application/json', true);
>
$this->_response->setBody("/*-secure-n" .
Zend_Json::encode($response) .
> "n*/");
> 
> $response really can be anything, a string, an array,
an object.
> 
> Cheers,
> Steven
> 
> -----Original Message-----
> From: Peter Lauri [mailto:peterlaurigmail.com] 
> Sent: Monday, 26 November 2007 7:17 AM
> To: Zend Framework General
> Subject: [fw-general] Ajax way
> 
> Hi,
> 
> I want to return json from an action, but I have hard
times finding out
> how to do it the best way with ZF. For the moment I
do:
> 
> 	function updateorderAction() {
> 		$i = 1;
> 		$o_divisiontable = new Division();
> 		foreach($_POST['divisioncontainer'] AS $i_divisionid)
{
> 			$o_division =
> $o_divisiontable->fetchRow("division_id =
> $i_divisionid");
> 			$o_division->priority = $i;
> 			$o_division->save();
> 			$i++;
> 		}
> 		$a_return = array("result", 1);
> 		echo json_encode($a_return);
> 		die;
> 	}
> 
> But that isn't the way, is it?
> 
> /Peter
> 
> 
> 

Ok, cool... But why is there a wrapper for a simple function
call for
the json, wouldn't json_encode($this->result) be simpler?
Or is there
something I don't get? 


On Mon, 2007-11-26 at 09:10 +1100, Simon Mundy wrote:
> <?= Zend_Json::encode($this->result) ?>

What do you mean? It was the same way to call in 5.1.x,
wasn't it?


On Mon, 2007-11-26 at 09:21 +1100, Simon Mundy wrote:
> Well, really only for PHP 5.1.x compatibility

or 


class AjaxController extends Zend_Controller_Action
{

   function updateorderAction()
   {
      ....
     
Zend_Controller_Front::getInstance()->setParam('noViewRen
derer',true);
     
$this->getResponse()->setBody(json_encode($this->re
sult));
   }



Le Mon, 26 Nov 2007 00:13:11 +0200,
Peter Lauri <peterlaurigmail.com> a écrit :

> Ok, cool... But why is there a wrapper for a simple
function call for
> the json, wouldn't json_encode($this->result) be
simpler? Or is there
> something I don't get? 
> 
> 
> On Mon, 2007-11-26 at 09:10 +1100, Simon Mundy wrote:
> > <?= Zend_Json::encode($this->result) ?>
> 

That one seams more "light" as it wouldn't require
any rendering of the
view. Or am I incorrect? Should I set the contenttype as
well? /Peter


On Sun, 2007-11-25 at 23:28 +0100, Stephane wrote:
> 
> class AjaxController extends Zend_Controller_Action
> {
> 
>    function updateorderAction()
>    {
>       ....
> 
>
Zend_Controller_Front::getInstance()->setParam('noViewRen
derer',true);
>      
$this->getResponse()->setBody(json_encode($this->re
sult));
>    }

Not built-in, but bundled, differnt  Still you
have to include the
extension to make it make it work...

On Mon, 2007-11-26 at 09:33 +1100, Simon Mundy wrote:
> Yes, but only if you had the extension - it was
built-in to 5.2

Hi Peter,

> But the problem is I am getting "edit.phtml"
not found if I don't  
> "die"
> the action. Or will this change if I do the setHeader
content-type?

I'm not getting into the JSON part of it but that issue just
sounds  
like you've not disabled the view renderer. Just adding:

...rest of your code...
echo json_encode($a_return);
$this->_helper->viewRenderer->setNoRender();

Should stop ViewRenderer trying to auto render a view
script.

http://framework
.zend.com/manual/en/ 
zend.controller.actionhelpers.html#zend.controller.actionhel
per.stockhel 
pers

Nick