(no subject)

On Tuesday May 30 2006 11:02, dvir schirman wrote:
> vector<float> new_vec(vec.size);

Missing parens:

vector<float> new_vec( vec.size() );
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It appears to me that you should use
	vector<float> new_vec( vec.size() );


On Tue, 30 May 2006, dvir schirman wrote:

> Hi
>
> I want to declare a new vector "new_vec" at
the same size as an existing
> vector "vec".
> I tried to use:
>
> vector<float> new_vec(vec.size);
>
> but I got the following error:
>
> test_b3.cpp:19: error: no matching function for call to
> `boost::numeric::ublas::vector<float,
> boost::numeric::ublas::unbounded_array<float,
std::allocator<float> >
> >::vector(<unknown type>)'
> ../boost/boost/numeric/ublas/vector.hpp:66: note:
candidates are:
> boost::numeric::ublas::vector<T, A>::vector(const
> boost::numeric::ublas::vector<T, A>&) [with T
= float, A =
> boost::numeric::ublas::unbounded_array<float,
std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:62: note:
> boost::numeric::ublas::vector<T,
A>::vector(typename A::size_type, const A&)
> [with T = float, A =
boost::numeric::ublas::unbounded_array<float,
> std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:57: note:
> boost::numeric::ublas::vector<T,
A>::vector(typename A::size_type) [with T =
> float, A =
boost::numeric::ublas::unbounded_array<float,
> std::allocator<float> >]
> ../boost/boost/numeric/ublas/vector.hpp:53: note:
> boost::numeric::ublas::vector<T, A>::vector()
[with T = float, A =
> boost::numeric::ublas::unbounded_array<float,
std::allocator<float> >]
>
> Thanks for your help.
>
> Dvir.
>
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